Do you remember this picture (3 quarks after one another):
The distance between A and B is somewhat around 13,6.
I can't measure it very well (I have to do it with a saté-pick!)
The triangels I used are 7 x 7 x 7 cm.
IF: we blow-up the construction by about 2mm for instance then the distance A-B would become 13,817580227...
That means it is: Pi * Phi * e !
It also means that the triangels would become 7,1 x 7,1 x 7,1 or something like that.
The triangel in the middle would stay the same.
See this picture: (wich, by the way, comes in the neighbourhood of a Reuleaux-triangle)
If thus the 3 quarks are a bit blown up, the R would become maybe 10!
So in overall:
the triangle in the middle from the cistercium (the doubleau)
has a sphere with a volume at the value of α = 137,035999
the circumsphere from the cirkel around the 3 quarks is 10 (maybe)
the distance from the axe between the 3 quarks is Pi x Phi x e
(3,141592653589... x 1,6180339887.... x 2,71828182845905... = 13,817580226750....)